Integrals: Difference between revisions

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# <math>\int \frac{du}{u^n\sqrt{a + bu}} = -\frac{\sqrt{a + bu}}{a(n-1)u^{n-1}} - \frac{b(2n-3)}{2a(n-1)}\int \frac{du}{u^{n-1}\sqrt{a + bu}}</math>
# <math>\int \frac{du}{u^n\sqrt{a + bu}} = -\frac{\sqrt{a + bu}}{a(n-1)u^{n-1}} - \frac{b(2n-3)}{2a(n-1)}\int \frac{du}{u^{n-1}\sqrt{a + bu}}</math>
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=== Trigonometric Forms: ===
# <math>\int \sin^2 u\, du = \tfrac{1}{2}u - \tfrac{1}{4}\sin 2u + C</math>
# <math>\int \cos^2 u\, du = \tfrac{1}{2}u + \tfrac{1}{4}\sin 2u + C</math>
# <math>\int \tan^2 u\, du = \tan u - u + C</math>
# <math>\int \cot^2 u\, du = -\cot u - u + C</math>
# <math>\int \sin^3 u\, du = -\tfrac{1}{3}(2 + \sin^2 u)\cos u + C</math>
# <math>\int \cos^3 u\, du = \tfrac{1}{3}(2 + \cos^2 u)\sin u + C</math>
# <math>\int \tan^3 u\, du = \tfrac{1}{2}\tan^2 u + \ln|\cos u| + C</math>
# <math>\int \cot^3 u\, du = -\tfrac{1}{2}\cot^2 u - \ln|\sin u| + C</math>
# <math>\int \sec^3 u\, du = \tfrac{1}{2}\sec u\tan u + \tfrac{1}{2}\ln|\sec u + \tan u| + C</math>
# <math>\int \csc^3 u\, du = -\tfrac{1}{2}\csc u\cot u + \tfrac{1}{2}\ln|\csc u - \cot u| + C</math>
# <math>\int \sin^n u\, du = -\frac{1}{n}\sin^{n-1}u\cos u + \frac{n-1}{n}\int \sin^{n-2}u\, du</math>
# <math>\int \cos^n u\, du = \frac{1}{n}\cos^{n-1}u\sin u + \frac{n-1}{n}\int \cos^{n-2}u\, du</math>
# <math>\int \tan^n u\, du = \frac{1}{n-1}\tan^{n-1}u - \int \tan^{n-2}u\, du</math>
# <math>\int \cot^n u\, du = \frac{-1}{n-1}\cot^{n-1}u - \int \cot^{n-2}u\, du</math>
# <math>\int \sec^n u\, du = \frac{1}{n-1}\tan u\sec^{n-2}u + \frac{n-2}{n-1}\int \sec^{n-2}u\, du</math>
# <math>\int \csc^n u\, du = \frac{-1}{n-1}\cot u\csc^{n-2}u + \frac{n-2}{n-1}\int \csc^{n-2}u\, du</math>
# <math>\int \sin au\sin bu\, du = \frac{\sin(a-b)u}{2(a-b)} - \frac{\sin(a+b)u}{2(a+b)} + C</math>
# <math>\int \cos au\cos bu\, du = \frac{\sin(a-b)u}{2(a-b)} + \frac{\sin(a+b)u}{2(a+b)} + C</math>
# <math>\int \sin au\cos bu\, du = -\frac{\cos(a-b)u}{2(a-b)} - \frac{\cos(a+b)u}{2(a+b)} + C</math>
# <math>\int u\sin u\, du = \sin u - u\cos u + C</math>
# <math>\int u\cos u\, du = \cos u + u\sin u + C</math>
# <math>\int u^n\sin u\, du = -u^n\cos u + n\int u^{n-1}\cos u\, du</math>
# <math>\int u^n\cos u\, du = u^n\sin u - n\int u^{n-1}\sin u\, du</math>
# <math>\int \sin^n u\cos^m u\, du = -\frac{\sin^{n-1}u\cos^{m+1}u}{n+m} + \frac{n-1}{n+m}\int \sin^{n-2}u\cos^m u\, du</math>
{{indent|40}}
<math>= \frac{\sin^{n+1}u\cos^{m-1}u}{n+m} + \frac{m-1}{n+m}\int \sin^n u\cos^{m-2}u\, du</math>
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== To Do ==
== To Do ==
*Antiderivative DB search system.
*Antiderivative DB search system.
*Find a use for the white-space on the right of the page.
*Find a use for the white-space on the right of the page.
*Integral Isolating System for easy reference/copying.
*Integral Isolating System for easy reference/copying.

Revision as of 16:24, 24 May 2026

Integral Forms & Antiderivatives

Basic Forms:

  1. udv=uvvdu
  2. undu=un+1n+1+C,(n1)
  3. duu=ln|u|+C
  4. eudu=eu+C
  5. audu=aulna+C
  6. sinudu=cosu+C
  7. cosudu=sinu+C
  8. sec2udu=tanu+C
  9. csc2udu=cotu+C
  10. secutanudu=secu+C
  11. cscucotudu=cscu+C
  12. tanudu=ln|secu|+C
  13. cotudu=ln|sinu|+C
  14. secudu=ln|secu+tanu|+C
  15. cscudu=ln|cscucotu|+C
  16. dua2u2=sin1ua+C,(a>0)
  17. dua2+u2=1atan1ua+C
  18. duuu2a2=1asec1ua+C
  19. dua2u2=12aln|u+aua|+C
  20. duu2a2=12aln|uau+a|+C


Forms Involving: a2+u2, a>0

  1. a2+u2du=u2a2+u2+a22ln(u+a2+u2)+C
  2. u2a2+u2du=u8(a2+2u2)a2+u2a48ln(u+a2+u2)+C
  3. a2+u2udu=a2+u2aln|a+a2+u2u|+C
  4. a2+u2u2du=a2+u2u+ln(u+a2+u2)+C
  5. dua2+u2=ln(u+a2+u2)+C
  6. u2dua2+u2=u2a2+u2a22ln(u+a2+u2)+C
  7. duua2+u2=1aln|a2+u2+au|+C
  8. duu2a2+u2=a2+u2a2u+C
  9. du(a2+u2)3/2=ua2a2+u2+C


Forms Involving: a2u2, a>0

  1. a2u2du=u2a2u2+a22sin1ua+C
  2. u2a2u2du=u8(2u2a2)a2u2+a48sin1ua+C
  3. a2u2udu=a2u2aln|a+a2u2u|+C
  4. a2u2u2du=1ua2u2sin1ua+C
  5. u2dua2u2=u2a2u2+a22sin1ua+C
  6. duua2u2=1aln|a+a2u2u|+C
  7. duu2a2u2=1a2ua2u2+C
  8. (a2u2)3/2du=u8(2u25a2)a2u2+3a48sin1ua+C
  9. du(a2u2)3/2=ua2a2u2+C


Forms Involving: u2a2, a>0

  1. u2a2du=u2u2a2a22ln|u+u2a2|+C
  2. u2u2a2du=u8(2u2a2)u2a2a48ln|u+u2a2|+C
  3. u2a2udu=u2a2acos1a|u|+C
  4. u2a2u2du=u2a2u+ln|u+u2a2|+C
  5. duu2a2=ln|u+u2a2|+C
  6. u2duu2a2=u2u2a2+a22ln|u+u2a2|+C
  7. duu2u2a2=u2a2a2u+C
  8. du(u2a2)3/2=ua2u2a2+C


Forms Involving: a+bu

  1. udua+bu=1b2(a+bualn|a+bu|)+C
  2. u2dua+bu=12b3[(a+bu)24a(a+bu)+2a2ln|a+bu|]+C
  3. duu(a+bu)=1aln|ua+bu|+C
  4. duu2(a+bu)=1au+ba2ln|a+buu|+C
  5. udu(a+bu)2=ab2(a+bu)+1b2ln|a+bu|+C
  6. duu(a+bu)2=1a(a+bu)1a2ln|a+buu|+C
  7. u2du(a+bu)2=1b3(a+bua2a+bu2aln|a+bu|)+C
  8. ua+budu=215b2(3bu2a)(a+bu)3/2+C
  9. udua+bu=23b2(bu2a)a+bu+C
  10. u2dua+bu=215b3(8a2+3b2u24abu)a+bu+C
  11. duua+bu={1aln|a+buaa+bu+a|+Cif a>02atan1a+bua+Cif a<0
  12. a+buudu=2a+bu+aduua+bu
  13. a+buu2du=a+buu+b2duua+bu
  14. una+budu=2b(2n+3)[un(a+bu)3/2naun1a+budu]
  15. undua+bu=2una+bub(2n+1)2nab(2n+1)un1dua+bu
  16. duuna+bu=a+bua(n1)un1b(2n3)2a(n1)duun1a+bu


Trigonometric Forms:

  1. sin2udu=12u14sin2u+C
  2. cos2udu=12u+14sin2u+C
  3. tan2udu=tanuu+C
  4. cot2udu=cotuu+C
  5. sin3udu=13(2+sin2u)cosu+C
  6. cos3udu=13(2+cos2u)sinu+C
  7. tan3udu=12tan2u+ln|cosu|+C
  8. cot3udu=12cot2uln|sinu|+C
  9. sec3udu=12secutanu+12ln|secu+tanu|+C
  10. csc3udu=12cscucotu+12ln|cscucotu|+C
  11. sinnudu=1nsinn1ucosu+n1nsinn2udu
  12. cosnudu=1ncosn1usinu+n1ncosn2udu
  13. tannudu=1n1tann1utann2udu
  14. cotnudu=1n1cotn1ucotn2udu
  15. secnudu=1n1tanusecn2u+n2n1secn2udu
  16. cscnudu=1n1cotucscn2u+n2n1cscn2udu
  17. sinausinbudu=sin(ab)u2(ab)sin(a+b)u2(a+b)+C
  18. cosaucosbudu=sin(ab)u2(ab)+sin(a+b)u2(a+b)+C
  19. sinaucosbudu=cos(ab)u2(ab)cos(a+b)u2(a+b)+C
  20. usinudu=sinuucosu+C
  21. ucosudu=cosu+usinu+C
  22. unsinudu=uncosu+nun1cosudu
  23. uncosudu=unsinunun1sinudu
  24. sinnucosmudu=sinn1ucosm+1un+m+n1n+msinn2ucosmudu

=sinn+1ucosm1un+m+m1n+msinnucosm2udu

To Do

  • Antiderivative DB search system.
  • Find a use for the white-space on the right of the page.
  • Integral Isolating System for easy reference/copying.