Integrals: Difference between revisions

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== Single Integrals ==
=== Space Curves: ===
{{indent|width=1em}}'''Arclength:'''&nbsp; <math>\int\limits_{a}^{b}\left \Vert \overrightarrow{r}(t) \right \| dt</math></div>
{{indent|width=1em}}'''Scalar Line Integral:'''&nbsp; <math>\int_Cf ds = \int\limits_{a}^{b} f(\overrightarrow{r}(t))*\left \Vert \overrightarrow{r}(t)' \right \| dt</math></div>
<br>
== Double Integrals ==
== Triple Integrals ==
== Integral Theorems ==


== Integral Forms & Antiderivatives ==
== Integral Forms & Antiderivatives ==
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# <math>\int \frac{u\, du}{\sqrt{a + bu}} = \frac{2}{3b^2}(bu - 2a)\sqrt{a + bu} + C</math>
# <math>\int \frac{u\, du}{\sqrt{a + bu}} = \frac{2}{3b^2}(bu - 2a)\sqrt{a + bu} + C</math>
# <math>\int \frac{u^2\, du}{\sqrt{a + bu}} = \frac{2}{15b^3}(8a^2 + 3b^2u^2 - 4abu)\sqrt{a + bu} + C</math>
# <math>\int \frac{u^2\, du}{\sqrt{a + bu}} = \frac{2}{15b^3}(8a^2 + 3b^2u^2 - 4abu)\sqrt{a + bu} + C</math>
# <math>\int \frac{du}{u\sqrt{a + bu}} = \begin{cases} \dfrac{1}{\sqrt{a}}\ln\left|\dfrac{\sqrt{a + bu} - \sqrt{a}}{\sqrt{a + bu} + \sqrt{a}}\right| + C & \text{if } a > 0 \\[6pt] \dfrac{2}{\sqrt{-a}}\tan^{-1}\sqrt{\dfrac{a + bu}{-a}} + C & \text{if } a < 0 \end{cases}</math>
# <math>\int \frac{du}{u\sqrt{a + bu}} = \begin{cases} \dfrac{1}{\sqrt{a}}\ln\left|\dfrac{\sqrt{a + bu} - \sqrt{a}}{\sqrt{a + bu} + \sqrt{a}}\right| + C & (\text{if } a > 0) \\[6pt] \dfrac{2}{\sqrt{-a}}\tan^{-1}\sqrt{\dfrac{a + bu}{-a}} + C & (\text{if } a < 0) \end{cases}</math>
# <math>\int \frac{\sqrt{a + bu}}{u}\, du = 2\sqrt{a + bu} + a\int \frac{du}{u\sqrt{a + bu}}</math>
# <math>\int \frac{\sqrt{a + bu}}{u}\, du = 2\sqrt{a + bu} + a\int \frac{du}{u\sqrt{a + bu}}</math>
# <math>\int \frac{\sqrt{a + bu}}{u^2}\, du = -\frac{\sqrt{a + bu}}{u} + \frac{b}{2}\int \frac{du}{u\sqrt{a + bu}}</math>
# <math>\int \frac{\sqrt{a + bu}}{u^2}\, du = -\frac{\sqrt{a + bu}}{u} + \frac{b}{2}\int \frac{du}{u\sqrt{a + bu}}</math>
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# <math>\int u^n\sin u\, du = -u^n\cos u + n\int u^{n-1}\cos u\, du</math>
# <math>\int u^n\sin u\, du = -u^n\cos u + n\int u^{n-1}\cos u\, du</math>
# <math>\int u^n\cos u\, du = u^n\sin u - n\int u^{n-1}\sin u\, du</math>
# <math>\int u^n\cos u\, du = u^n\sin u - n\int u^{n-1}\sin u\, du</math>
# <math>\int \sin^n u\cos^m u\, du = -\frac{\sin^{n-1}u\cos^{m+1}u}{n+m} + \frac{n-1}{n+m}\int \sin^{n-2}u\cos^m u\, du</math>  
# <math>\int \sin^n u\cos^m u\, du = -\frac{\sin^{n-1}u\cos^{m+1}u}{n+m} + \frac{n-1}{n+m}\int \sin^{n-2}u\cos^m u\, du</math>
{{indent|width=11em}}&nbsp;<math>= \frac{\sin^{n+1}u\cos^{m-1}u}{n+m} + \frac{m-1}{n+m}\int \sin^n u\cos^{m-2}u\, du</math></div>
{{indent|width=11em}}&nbsp;<math>= \frac{\sin^{n+1}u\cos^{m-1}u}{n+m} + \frac{m-1}{n+m}\int \sin^n u\cos^{m-2}u\, du</math></div>
<br>
=== Inverse Trigonometric Forms: ===
# <math>\int \sin^{-1}u\, du = u\sin^{-1}u + \sqrt{1 - u^2} + C</math>
# <math>\int \cos^{-1}u\, du = u\cos^{-1}u - \sqrt{1 - u^2} + C</math>
# <math>\int \tan^{-1}u\, du = u\tan^{-1}u - \tfrac{1}{2}\ln(1 + u^2) + C</math>
# <math>\int u\sin^{-1}u\, du = \frac{2u^2 - 1}{4}\sin^{-1}u + \frac{u\sqrt{1 - u^2}}{4} + C</math>
# <math>\int u\cos^{-1}u\, du = \frac{2u^2 - 1}{4}\cos^{-1}u - \frac{u\sqrt{1 - u^2}}{4} + C</math>
# <math>\int u\tan^{-1}u\, du = \frac{u^2 + 1}{2}\tan^{-1}u - \frac{u}{2} + C</math>
# <math>\int u^n\sin^{-1}u\, du = \frac{1}{n+1}\left[u^{n+1}\sin^{-1}u - \int \frac{u^{n+1}\, du}{\sqrt{1 - u^2}}\right], \quad (n \neq -1)</math>
# <math>\int u^n\cos^{-1}u\, du = \frac{1}{n+1}\left[u^{n+1}\cos^{-1}u + \int \frac{u^{n+1}\, du}{\sqrt{1 - u^2}}\right], \quad (n \neq -1)</math>
# <math>\int u^n\tan^{-1}u\, du = \frac{1}{n+1}\left[u^{n+1}\tan^{-1}u - \int \frac{u^{n+1}\, du}{1 + u^2}\right], \quad (n \neq -1)</math>
</br>
=== Exponential and Logarithmic Forms: ===
# <math>\int ue^{au}\, du = \frac{1}{a^2}(au - 1)e^{au} + C</math>
# <math>\int u^n e^{au}\, du = \frac{1}{a}u^n e^{au} - \frac{n}{a}\int u^{n-1}e^{au}\, du</math>
# <math>\int e^{au}\sin bu\, du = \frac{e^{au}}{a^2 + b^2}(a\sin bu - b\cos bu) + C</math>
# <math>\int e^{au}\cos bu\, du = \frac{e^{au}}{a^2 + b^2}(a\cos bu + b\sin bu) + C</math>
# <math>\int \ln u\, du = u\ln u - u + C</math>
# <math>\int u^n\ln u\, du = \frac{u^{n+1}}{(n+1)^2}\left[(n+1)\ln u - 1\right] + C</math>
# <math>\int \frac{1}{u\ln u}\, du = \ln|\ln u| + C</math>
<br>
=== Hyperbolic Forms: ===
# <math>\int \sinh u\, du = \cosh u + C</math>
# <math>\int \cosh u\, du = \sinh u + C</math>
# <math>\int \tanh u\, du = \ln\cosh u + C</math>
# <math>\int \coth u\, du = \ln|\sinh u| + C</math>
# <math>\int \text{sech}\, u\, du = \tan^{-1}|\sinh u| + C</math>
# <math>\int \text{csch}\, u\, du = \ln\left|\tanh\tfrac{1}{2}u\right| + C</math>
# <math>\int \text{sech}^2 u\, du = \tanh u + C</math>
# <math>\int \text{csch}^2 u\, du = -\coth u + C</math>
# <math>\int \text{sech}\, u\tanh u\, du = -\text{sech}\, u + C</math>
# <math>\int \text{csch}\, u\coth u\, du = -\text{csch}\, u + C</math>
<br>
=== Forms Involving: <math>\sqrt{2au - u^2},\ a > 0</math> ===
# <math>\int \sqrt{2au - u^2}\, du = \frac{u - a}{2}\sqrt{2au - u^2} + \frac{a^2}{2}\cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int u\sqrt{2au - u^2}\, du = \frac{2u^2 - au - 3a^2}{6}\sqrt{2au - u^2} + \frac{a^3}{2}\cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{\sqrt{2au - u^2}}{u}\, du = \sqrt{2au - u^2} + a\cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{\sqrt{2au - u^2}}{u^2}\, du = -\frac{2\sqrt{2au - u^2}}{u} - \cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{du}{\sqrt{2au - u^2}} = \cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{u\, du}{\sqrt{2au - u^2}} = -\sqrt{2au - u^2} + a\cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{u^2\, du}{\sqrt{2au - u^2}} = -\frac{(u + 3a)}{2}\sqrt{2au - u^2} + \frac{3a^2}{2}\cos^{-1}\!\left(\frac{a - u}{a}\right) + C</math>
# <math>\int \frac{du}{u\sqrt{2au - u^2}} = -\frac{\sqrt{2au - u^2}}{au} + C</math>
<br>
== To Do ==
== To Do ==
*Antiderivative DB search system.
*Antiderivative DB search system.
*Find a use for the white-space on the right of the page.
*Find a use for the white-space on the right of the page.
*Integral Isolating System for easy reference/copying.
*Integral Isolating System for easy reference/copying.

Latest revision as of 17:21, 24 May 2026

Single Integrals

Space Curves:

Arclength:  abr(t)dt
Scalar Line Integral:  Cfds=abf(r(t))*r(t)dt


Double Integrals

Triple Integrals

Integral Theorems

Integral Forms & Antiderivatives

Basic Forms:

  1. udv=uvvdu
  2. undu=un+1n+1+C,(n1)
  3. duu=ln|u|+C
  4. eudu=eu+C
  5. audu=aulna+C
  6. sinudu=cosu+C
  7. cosudu=sinu+C
  8. sec2udu=tanu+C
  9. csc2udu=cotu+C
  10. secutanudu=secu+C
  11. cscucotudu=cscu+C
  12. tanudu=ln|secu|+C
  13. cotudu=ln|sinu|+C
  14. secudu=ln|secu+tanu|+C
  15. cscudu=ln|cscucotu|+C
  16. dua2u2=sin1ua+C,(a>0)
  17. dua2+u2=1atan1ua+C
  18. duuu2a2=1asec1ua+C
  19. dua2u2=12aln|u+aua|+C
  20. duu2a2=12aln|uau+a|+C


Forms Involving: a2+u2, a>0

  1. a2+u2du=u2a2+u2+a22ln(u+a2+u2)+C
  2. u2a2+u2du=u8(a2+2u2)a2+u2a48ln(u+a2+u2)+C
  3. a2+u2udu=a2+u2aln|a+a2+u2u|+C
  4. a2+u2u2du=a2+u2u+ln(u+a2+u2)+C
  5. dua2+u2=ln(u+a2+u2)+C
  6. u2dua2+u2=u2a2+u2a22ln(u+a2+u2)+C
  7. duua2+u2=1aln|a2+u2+au|+C
  8. duu2a2+u2=a2+u2a2u+C
  9. du(a2+u2)3/2=ua2a2+u2+C


Forms Involving: a2u2, a>0

  1. a2u2du=u2a2u2+a22sin1ua+C
  2. u2a2u2du=u8(2u2a2)a2u2+a48sin1ua+C
  3. a2u2udu=a2u2aln|a+a2u2u|+C
  4. a2u2u2du=1ua2u2sin1ua+C
  5. u2dua2u2=u2a2u2+a22sin1ua+C
  6. duua2u2=1aln|a+a2u2u|+C
  7. duu2a2u2=1a2ua2u2+C
  8. (a2u2)3/2du=u8(2u25a2)a2u2+3a48sin1ua+C
  9. du(a2u2)3/2=ua2a2u2+C


Forms Involving: u2a2, a>0

  1. u2a2du=u2u2a2a22ln|u+u2a2|+C
  2. u2u2a2du=u8(2u2a2)u2a2a48ln|u+u2a2|+C
  3. u2a2udu=u2a2acos1a|u|+C
  4. u2a2u2du=u2a2u+ln|u+u2a2|+C
  5. duu2a2=ln|u+u2a2|+C
  6. u2duu2a2=u2u2a2+a22ln|u+u2a2|+C
  7. duu2u2a2=u2a2a2u+C
  8. du(u2a2)3/2=ua2u2a2+C


Forms Involving: a+bu

  1. udua+bu=1b2(a+bualn|a+bu|)+C
  2. u2dua+bu=12b3[(a+bu)24a(a+bu)+2a2ln|a+bu|]+C
  3. duu(a+bu)=1aln|ua+bu|+C
  4. duu2(a+bu)=1au+ba2ln|a+buu|+C
  5. udu(a+bu)2=ab2(a+bu)+1b2ln|a+bu|+C
  6. duu(a+bu)2=1a(a+bu)1a2ln|a+buu|+C
  7. u2du(a+bu)2=1b3(a+bua2a+bu2aln|a+bu|)+C
  8. ua+budu=215b2(3bu2a)(a+bu)3/2+C
  9. udua+bu=23b2(bu2a)a+bu+C
  10. u2dua+bu=215b3(8a2+3b2u24abu)a+bu+C
  11. duua+bu={1aln|a+buaa+bu+a|+C(if a>0)2atan1a+bua+C(if a<0)
  12. a+buudu=2a+bu+aduua+bu
  13. a+buu2du=a+buu+b2duua+bu
  14. una+budu=2b(2n+3)[un(a+bu)3/2naun1a+budu]
  15. undua+bu=2una+bub(2n+1)2nab(2n+1)un1dua+bu
  16. duuna+bu=a+bua(n1)un1b(2n3)2a(n1)duun1a+bu


Trigonometric Forms:

  1. sin2udu=12u14sin2u+C
  2. cos2udu=12u+14sin2u+C
  3. tan2udu=tanuu+C
  4. cot2udu=cotuu+C
  5. sin3udu=13(2+sin2u)cosu+C
  6. cos3udu=13(2+cos2u)sinu+C
  7. tan3udu=12tan2u+ln|cosu|+C
  8. cot3udu=12cot2uln|sinu|+C
  9. sec3udu=12secutanu+12ln|secu+tanu|+C
  10. csc3udu=12cscucotu+12ln|cscucotu|+C
  11. sinnudu=1nsinn1ucosu+n1nsinn2udu
  12. cosnudu=1ncosn1usinu+n1ncosn2udu
  13. tannudu=1n1tann1utann2udu
  14. cotnudu=1n1cotn1ucotn2udu
  15. secnudu=1n1tanusecn2u+n2n1secn2udu
  16. cscnudu=1n1cotucscn2u+n2n1cscn2udu
  17. sinausinbudu=sin(ab)u2(ab)sin(a+b)u2(a+b)+C
  18. cosaucosbudu=sin(ab)u2(ab)+sin(a+b)u2(a+b)+C
  19. sinaucosbudu=cos(ab)u2(ab)cos(a+b)u2(a+b)+C
  20. usinudu=sinuucosu+C
  21. ucosudu=cosu+usinu+C
  22. unsinudu=uncosu+nun1cosudu
  23. uncosudu=unsinunun1sinudu
  24. sinnucosmudu=sinn1ucosm+1un+m+n1n+msinn2ucosmudu
 =sinn+1ucosm1un+m+m1n+msinnucosm2udu


Inverse Trigonometric Forms:

  1. sin1udu=usin1u+1u2+C
  2. cos1udu=ucos1u1u2+C
  3. tan1udu=utan1u12ln(1+u2)+C
  4. usin1udu=2u214sin1u+u1u24+C
  5. ucos1udu=2u214cos1uu1u24+C
  6. utan1udu=u2+12tan1uu2+C
  7. unsin1udu=1n+1[un+1sin1uun+1du1u2],(n1)
  8. uncos1udu=1n+1[un+1cos1u+un+1du1u2],(n1)
  9. untan1udu=1n+1[un+1tan1uun+1du1+u2],(n1)


Exponential and Logarithmic Forms:

  1. ueaudu=1a2(au1)eau+C
  2. uneaudu=1auneaunaun1eaudu
  3. eausinbudu=eaua2+b2(asinbubcosbu)+C
  4. eaucosbudu=eaua2+b2(acosbu+bsinbu)+C
  5. lnudu=ulnuu+C
  6. unlnudu=un+1(n+1)2[(n+1)lnu1]+C
  7. 1ulnudu=ln|lnu|+C


Hyperbolic Forms:

  1. sinhudu=coshu+C
  2. coshudu=sinhu+C
  3. tanhudu=lncoshu+C
  4. cothudu=ln|sinhu|+C
  5. sechudu=tan1|sinhu|+C
  6. cschudu=ln|tanh12u|+C
  7. sech2udu=tanhu+C
  8. csch2udu=cothu+C
  9. sechutanhudu=sechu+C
  10. cschucothudu=cschu+C


Forms Involving: 2auu2, a>0

  1. 2auu2du=ua22auu2+a22cos1(aua)+C
  2. u2auu2du=2u2au3a262auu2+a32cos1(aua)+C
  3. 2auu2udu=2auu2+acos1(aua)+C
  4. 2auu2u2du=22auu2ucos1(aua)+C
  5. du2auu2=cos1(aua)+C
  6. udu2auu2=2auu2+acos1(aua)+C
  7. u2du2auu2=(u+3a)22auu2+3a22cos1(aua)+C
  8. duu2auu2=2auu2au+C


To Do

  • Antiderivative DB search system.
  • Find a use for the white-space on the right of the page.
  • Integral Isolating System for easy reference/copying.